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4n^2-76n+360=0
a = 4; b = -76; c = +360;
Δ = b2-4ac
Δ = -762-4·4·360
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-4}{2*4}=\frac{72}{8} =9 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+4}{2*4}=\frac{80}{8} =10 $
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